(4x+5)(x^2+2x-8)=0

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Solution for (4x+5)(x^2+2x-8)=0 equation: 


Simplifying
(4x + 5)(x2 + 2x + -8) = 0

Reorder the terms:
(5 + 4x)(x2 + 2x + -8) = 0

Reorder the terms:
(5 + 4x)(-8 + 2x + x2) = 0

Multiply (5 + 4x) * (-8 + 2x + x2)
(5(-8 + 2x + x2) + 4x * (-8 + 2x + x2)) = 0
((-8 * 5 + 2x * 5 + x2 * 5) + 4x * (-8 + 2x + x2)) = 0
((-40 + 10x + 5x2) + 4x * (-8 + 2x + x2)) = 0
(-40 + 10x + 5x2 + (-8 * 4x + 2x * 4x + x2 * 4x)) = 0
(-40 + 10x + 5x2 + (-32x + 8x2 + 4x3)) = 0

Reorder the terms:
(-40 + 10x + -32x + 5x2 + 8x2 + 4x3) = 0

Combine like terms: 10x + -32x = -22x
(-40 + -22x + 5x2 + 8x2 + 4x3) = 0

Combine like terms: 5x2 + 8x2 = 13x2
(-40 + -22x + 13x2 + 4x3) = 0

Solving
-40 + -22x + 13x2 + 4x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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